3x3 + 6x2 - 24x
= 3x(x2 + 2x - 8)
= 3x(x2 + 4x - 2x - 8)
= 3x[ x(x + 4) - 2(x + 4) ]
= 3x(x - 2)(x + 4)
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Since you add up the 'x''s (i.e. (2x) (3x) (4x) = 24x cubed) 6x2
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
15x2-56 = 88+6x2 15x2-6x2-56-88 = 0 9x2-144 = 0 Divide all terms by 9:- x2-16 = 0 (x-4)(x+4) = 0 x = 4 or x = -4
Im assuming the "6x2" is supposed to be 6x squared. The factored form would be (2x+1) (3x-8)