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3x3 + 6x2 - 24x
= 3x(x2 + 2x - 8)
= 3x(x2 + 4x - 2x - 8)
= 3x[ x(x + 4) - 2(x + 4) ]
= 3x(x - 2)(x + 4)
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∙ 13y ago
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3X x 2X?
Since you add up the 'x''s (i.e. (2x) (3x) (4x) = 24x cubed) 6x2
What is 3x plus 1 times 2x plus 4?
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
X3 plus 6x2 - 4x - 24 factor completely?
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
What are the x-solutions for the equation below 15x2 - 56 equals 88 plus 6x2?
15x2-56 = 88+6x2 15x2-6x2-56-88 = 0 9x2-144 = 0 Divide all terms by 9:- x2-16 = 0 (x-4)(x+4) = 0 x = 4 or x = -4
What is the correct factored form of the given equation 6x2 -13x - 8 equals 0?
Im assuming the "6x2" is supposed to be 6x squared. The factored form would be (2x+1) (3x-8)
What is the factorization of 3x3 plus 6x2 24x?
3X3 + 6X2 - 24X3X(X2 + 2X - 8)3X(X + 4)(X - 2)================assuming that last term was - 24X
-3x3-6x2 plus 189x factor completely?
-3x3 - 6x2 + 189x = -3x(x2 + 2x - 63) = -3x(x + 9)(x - 7)
What is -3x3 plus 6x2 plus 6x plus 9 equals?
One-houndred and thirty five.
What is the factorization of 3x3 plus 6x2 - 12x?
3x(x2 + 2x - 4)
Factor 3x3 plus 6x2 plus 5x plus 10?
(3x^2+5)(x+2). APEX CHEATERS UNIT.....
How do you solve for x in the equation 3 over x square plus 3 over 4x minus 3 over 1 equals 6 over 2x square minus 6 over 3x plus 6 over 5?
3/(x2+4x-1) = 6/(2x2-3x+5) Cross - multiply in order to eliminate the fractions: 6*(x2+4x-1) = 3*(2x2-3x+5) 6x2+24x-6 = 6x2-9x+15 6x2-6x2+24x+9x = 15+6 33x = 21 x = 21/33 => x = 7/11
What is the answer to 9 plus 6x2?
9+6x2=21
What is 6x2-24x-72 factored?
6(x2 -4x - 12) 6(x-6)(x+2)
3X x 2X?
Since you add up the 'x''s (i.e. (2x) (3x) (4x) = 24x cubed) 6x2
How do you factor 6x2 plus 10x?
6x2 + 10x = 2x(3x + 5)
How do you factor 6x2 plus 2x-28?
6x2=12 2x-28=?
Are 3x2 plus 4 and 6x2 inverses?
No.
