Since you add up the 'x''s (i.e. (2x) (3x) (4x) = 24x cubed) 6x2
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x2/(3x2 - 5x - 2) - [2x/ (3x + 1)][1/(x - 2)] = x2/(3x2 - 6x + x - 2) - 2x/(3x + 1)(x - 2) = x2/[3x(x - 2) + (x - 2)] - 2x/(3x + 1)(x - 2) = x2/(3x + 1)(x - 2) - 2x/(3x + 1)(x - 2) = (x2 - 2x)/(3x + 1)(x - 2) = x(x - 2)/(3x + 1)(x - 2) = x/(3x + 1)
x + 2x = 33 3x = 33 3x/3 = 33/3 x = 11
3x-2 = 2x+3 3x-2x = 3+2 x = 5
2x+x+5+3x-6=6x-1
If you mean: 2x-3 = 3x+3 then x = -6