x2/(3x2 - 5x - 2) - [2x/ (3x + 1)][1/(x - 2)] = x2/(3x2 - 6x + x - 2) - 2x/(3x + 1)(x - 2) = x2/[3x(x - 2) + (x - 2)] - 2x/(3x + 1)(x - 2) = x2/(3x + 1)(x - 2) - 2x/(3x + 1)(x - 2) = (x2 - 2x)/(3x + 1)(x - 2) = x(x - 2)/(3x + 1)(x - 2) = x/(3x + 1)
x + 2x = 33 3x = 33 3x/3 = 33/3 x = 11
3x-2 = 2x+3 3x-2x = 3+2 x = 5
2x+x+5+3x-6=6x-1
If you mean: 2x-3 = 3x+3 then x = -6
2x - 3x = -x
(2x x 3x) x 2 = 12x (2x times 3x times 2)
10 - 3x = x - 2x + 40 10 - 3x = - x + 40 10 - 40 = 3x - x -30 = 2x -15 = x
Let's dive into this problem: Given numbers/terms are: -2x and x.. We are asked to subtract both.. -2x-x = -(2+1)x = -3x.. Therefore, the answer is -3x..
3x + 2x - 8x + 2x = -x
-2x+20 = 3x 20 = 3x+2x 20 = 5x 4 = x So x = 4
3x - 2x + 4 = 0 3x - 2x = -4 x = -4
1 + 3x - x = x - 4 + 2x 1 + 4 = x + 2x - 3x + x 5 = x
2x minus 3x is equal to -x.
2x minus 3x is equal to -x.
3x+9=2x+10 3x+9-2x=10 9+x=10 x=1
3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6