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Assuming the missing symbols are pluses, that factors to (x + 4)(x + 1)
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∙ 9y ago
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What is the binomials is a factor of this trinomial x2 -5x plus 4?
x2-5x+4 = (x-1)(x-4) when factored
How do you solve x2 5x 4 in a descending order?
If you mean: x2+5x+4 = 0 then the solutions are x = -1 and x = -4
Solve by squaring X2 equals 5x plus 2?
To solve for x: x2 = 5x + 2 x2 - 5x = 2 x2 - 5x + (5/2)2 = 2 + (5/2)2 (x - 5/2)2 = 8/4 + 25/4 x - 5/2 = ± √(33/4) x = (5 ± √33) / 2
X2 plus 5x plus 4 equals 0?
-x2 + 5x - 4 = 0. Then, x2 - 5x + 4 = (x - 4)(x - 1) = 0; whence, x = 1 or 4. Checking, -1 + 5 - 4 = 0; and -16 + 20 - 4 = 0.
What are solutions to the equation x2 plus 4x-9 equals 5x plus 3?
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
What is the factorization of x2 plus 5x plus 4?
(x + 4)(x + 1)
What is the factorization of x2 - 5x - 36?
Assuming that x2 is x squared: (x - 9)(x + 4)
What is the factorization of the trinomial x2-5x-36?
It is (x - 9)*(x + 4)
What is the factorization of x2-5x plus 6?
(x-6)(x+1)
What is the complete factorization of x2 - 5x - 14?
(x - 7)(x + 2)
What is the binomials is a factor of this trinomial x2 -5x plus 4?
x2-5x+4 = (x-1)(x-4) when factored
What is the factorization of the trinomial x3 plus 13x2 plus 40x?
It is: (x2 + 5x) (x + 8)
How do you solve x2 5x 4 in a descending order?
If you mean: x2+5x+4 = 0 then the solutions are x = -1 and x = -4
Which of the binomials below is factor of this trinomial x2-5x plus 4 equals?
x2-5x+4 = (x-1)(x-4) when factord
What binomial is a factor to the trinomial x2 - 5x - 36?
When factored it is: (x-9)(x+4)
Solve by squaring X2 equals 5x plus 2?
To solve for x: x2 = 5x + 2 x2 - 5x = 2 x2 - 5x + (5/2)2 = 2 + (5/2)2 (x - 5/2)2 = 8/4 + 25/4 x - 5/2 = ± √(33/4) x = (5 ± √33) / 2
Integral of root of 4-x2?
2
