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Owen Kris

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3y ago
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15y ago

If you mean integral SQRT(4-x2)dx, 2arcsin(.5x)+.5xSQRT(4-x2).

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Q: Integral of root of 4-x2
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What is the square root of -4x2?

In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)


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