x2+7x+12
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
=3x * * * * * The correct answer is: x2 + 7x + 12 = (x + 3)(x + 4).
x2-7x+12 (x-3)(x-4)
(x + 5)(x + 2)
Divide all terms by 4:- x2+7x+12 = (x+3)(x+4) when factored
x^2 +7x+12 = (x+3)(x+4) when factored
-x2 + x + 42= -x2 + 7x - 6x + 42= 7x - x2 + 42 - 6x= x(7 - x) + 6(7 - x)= (7 - x)(x + 6)
x2-7x+6 = (x-1)(x-6) when factored.
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x2 + 7x + 6 = (x + 6) (x + 1)
x2-7x+12 = 0 (x-3)(x-4) = 0x=3,4