Q: X2 plus 7x plus 12

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=3x * * * * * The correct answer is: x2 + 7x + 12 = (x + 3)(x + 4).

x2-7x+12 (x-3)(x-4)

x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0

x2-7x+12 = 0 (x-3)(x-4) = 0x=3,4

It is (x-3)(x-4) when factored

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x2+7x+12

x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3

=3x * * * * * The correct answer is: x2 + 7x + 12 = (x + 3)(x + 4).

x2-7x+12 (x-3)(x-4)

Do you mean x2+7x+12? If so then it is: (x+3)(x+4)

x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0

x2-7x+12 = 0 (x-3)(x-4) = 0x=3,4

x2 + 7x + 6 = (x + 6) (x + 1)

The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth

(x + 3)(x + 4)

It is (x-3)(x-4) when factored

x2 + 7x - 8 = (x + 8)(x - 1)