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Q: How do you factor x2 plus 7x plus 6?

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x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3

-7x + 6 + 7x - 2 = 4

x2+9x+18 find factors of 18 that add up to 9, in this case 6&3 (x+6)(x+3)

The factors are (x + 6) and (x - 3)

3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.

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x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0

It is: (x+1)(x+6) when factored

x2- 7x + 6 = 0 factor, (x-6)(x-1) = 0 x = 6 x = 1

x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}

This is not factorable. You would have to do the quadratic formula for this problem.

i got 42 divided 7x

x^2 +7x+6 = (x+1)(x+6) when factored

-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)

-x2 + x + 42= -x2 + 7x - 6x + 42= 7x - x2 + 42 - 6x= x(7 - x) + 6(7 - x)= (7 - x)(x + 6)

You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)

x2-7x+6 = (x-1)(x-6) when factored.

x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3

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