249
To find the smallest, (n+2) + 5*n = -244 so the formula is n = -246/6
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
what is the formula to use to solve the product of two consecutive odd integers
There is no difference, only your outcome. The formula for both is x+2
Find two consecuitive integers whose sum is 89. To solve this problem, let x be the smaller of these integers. What is the larger of these two consecutive integers? In terms of x, write a formula that represents the sum of these two consecutive integers.
well its process is science of eratosthenes as i heard,,,,,, science of eratosthenes is the process of crossing out all multiples of 2,3,5&7 ERATOSTHENES is the one who discovered the formula for finding the sum of all integers from 1 to 100
One way to find out is write a formula. Let N and N+1 be the two integers, then N(N+1) = 182 N^2 + N - 182 = 0 This is a quadratic equation. If the factors are not obvious, (N -13)(N + 14) , then use the quadratic formula to find N. The factors tell you there are two possible solutions for N; 13 and -14. Now add 1 to these to get the two consecutive integers. 13 & 14 will work and -14 & -13 will work.
59 + 60 + 61 = 180 ---- To work out consecutive integers, use this formula: (x+1) + (x+2) + (x+3) = 180 ---> 3x + 6 = 180 ---> 3x = 174 ---> 174/3 = x = 58 so (58+1) = 59, (58 + 2) = 60, (58 + 3) = 61
The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
Actually, there are plenty of those. The oldest might be this well-known formula by Euler: n^2 - n + 41 gives a prime for all positive integers smaller than 41.
Let n be an integer, then two consecutive odd integers can be expressed as n and n+2. The equation can the be wrote as n2 + (n+2)2 = 202 = n2 +n2 + 4n +4 = 202 which implies 2n2 + 4n - 198 = 0 which implies n2 + 2n - 99 = 0 the quadratic formula can then be used to solve for n as n = (-2 +- (4 - 4*-99)^(1/2))/(2) = -1 +- (1/2)*(400)^(1/2) = - 1 +- 10 take the positive solution and you get n = 9 which implies your two consecutive integers are 9 and 11.
There isn't a formula for finding joules. It is a way for finding a force or giving an example.