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For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
what is the formula to use to solve the product of two consecutive odd integers
There is no difference, only your outcome. The formula for both is x+2
Find two consecuitive integers whose sum is 89. To solve this problem, let x be the smaller of these integers. What is the larger of these two consecutive integers? In terms of x, write a formula that represents the sum of these two consecutive integers.
well its process is science of eratosthenes as i heard,,,,,, science of eratosthenes is the process of crossing out all multiples of 2,3,5&7 ERATOSTHENES is the one who discovered the formula for finding the sum of all integers from 1 to 100
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210
One way to find out is write a formula. Let N and N+1 be the two integers, then N(N+1) = 182 N^2 + N - 182 = 0 This is a quadratic equation. If the factors are not obvious, (N -13)(N + 14) , then use the quadratic formula to find N. The factors tell you there are two possible solutions for N; 13 and -14. Now add 1 to these to get the two consecutive integers. 13 & 14 will work and -14 & -13 will work.
59 + 60 + 61 = 180 ---- To work out consecutive integers, use this formula: (x+1) + (x+2) + (x+3) = 180 ---> 3x + 6 = 180 ---> 3x = 174 ---> 174/3 = x = 58 so (58+1) = 59, (58 + 2) = 60, (58 + 3) = 61
The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
Actually, there are plenty of those. The oldest might be this well-known formula by Euler: n^2 - n + 41 gives a prime for all positive integers smaller than 41.
To find the numbers between 50 and 100 that are divisible by 3, we can use the formula for finding the number of integers divisible by a certain number within a range. The formula is (largest number - smallest number) / divisor + 1. In this case, the largest number is 99, the smallest number is 51, and the divisor is 3. Plugging these values into the formula, we get (99 - 51) / 3 + 1 = 16. Therefore, there are 16 numbers between 50 and 100 that are divisible by 3.