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The three integers, since they are consecutive, can be listed as a, a+1, and a+2.

Twice the first is 2a.

Three times the third is 3(a+2) = 3a+6.

First make a formula of the information given:

2a+(3a+6)= -24

Next, solve the formula:

5a + 6 = -24

Subtract 6 from each side.

5a = -30

Divide each side by 5.

a = -6

The three consecutive numbers are -6, -5, and -4.

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Q: How do you find three consecutive integers so that twice the first increased by three times the third will be -24?
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