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Best Answer

You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers.

2) Call the two consecutive integers "n" and "n+1", and solve the equation:

n(n+1)=210

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Wiki User

8y ago
This answer is:
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Itz Mhiz Ifeoluwa

Lvl 1
2y ago
I don't even understand it at all
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Itz Mhiz Ifeoluwa

Lvl 1
2y ago
Pls try to do more explainable
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lenpollock

Lvl 16
6mo ago

Let the integers by n & n+1

Their product is

n(n+1) = 210

n^2 + n = 210

n^2 + n - 210 = 0

Factor

( n - 14)(n + 15) = 0

n = 14 & n = -15

The consecutive integers being 14 & 15.

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Wiki User

8y ago

Yes, it is possible.

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Q: The product of two consecutive integers is 210?
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