You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers.
2) Call the two consecutive integers "n" and "n+1", and solve the equation:
n(n+1)=210
The two consecutive positive integers whose product is 380 are 19 x 20.
Yes, the integers are 12 and 13.
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
-10 -11
-8 -9
There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.
There is no set of two consecutive integers having a product of 14. Product means the result of multiplication.
There is no set of two consecutive integers equating to 200.
No, it is not. It is the sum of two consecutive integers: 46 and 47.
The two consecutive positive integers whose product is 380 are 19 x 20.
There are no two consecutive integers, negative or positive, whose product is 440.
Their product is 143.
what is the formula to use to solve the product of two consecutive odd integers
The two consecutive odd integers having a product of 99 are 9 and 11.
the two consecutive positive integers whose product is 380 19 20
The integers are 9 and 10.
The integers are 5 and 7.