The formula is
Un = n*(-1)n+1
-1,-2,-3 10-1=9 9-2=7 7-3=4
the formula is: Sn= n [2(A1)+(n - 1)d] 2 for example the given sequence is when A1 = 4 and n = 10 when d = 2 here is the solution: Sn = 4 [2(4)+(10 - 1)2] 2 Sn= 2 [6+(9)(2) Sn = 2 [6+18] Sn = 2 (24) Sn = 48 see?
Assuming each term is 3 MORE than the previous term t(n) = -13 + 3*n where n = 1, 2, 3, ...
The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.
a(n) = a(1) x r^n-1 In this case a(1) is 2 and r is 3 That makes the formula a(n) = 2 x 3^n-1
10-2x for x = 0, 1, 2, 3, ... Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.
-1,-2,-3 10-1=9 9-2=7 7-3=4
10
Type yourWhich choice is the explicit formula for the following geometric sequence? answer here...
the formula is: Sn= n [2(A1)+(n - 1)d] 2 for example the given sequence is when A1 = 4 and n = 10 when d = 2 here is the solution: Sn = 4 [2(4)+(10 - 1)2] 2 Sn= 2 [6+(9)(2) Sn = 2 [6+18] Sn = 2 (24) Sn = 48 see?
Finding the nth term is much simpler than it seems. For example, say you had the sequence: 1,4,7,10,13,16 Sequence 1 First we find the difference between the numbers. 1 (3) 4 (3) 7 (3) 10 (3) 13 (3) 16 The difference is the same: 3. So the start of are formula will be 3n. If it was 3n, the sequence would be 3,6,9,12,15,18 Sequence 2 But this is not our sequence. Notice that each number on sequence 2 is 2 more than sequence 1. this means are final formula will be: 3n+1 Test it out, it works!
10 - 4n
There is no formula, but I can point out that: between the numbers you get: +1,+2,+3,+4+5... so the next term would be +6 or 21
What is the formula for the number sequence 3 7 12 18 25...? This series is similar to the triangular number sequence 1 3 6 10 15 21.... with the formula n(n+1)/2. So for the number sequence 3 7 12 18 25... I derived a new formula by adding 2n to n(n+1)/2 to get this simplified formula: [(n*n) + 5n)]/2 (or n squared plus 5n all divided by two) when n=1, we get [(1*1) + 5(1)]/2=(1+5)/2= 6/2=3 when n=2, we get [(2*2) + 5(2)]/2=(4+10)/2=14/2=7 when n=3, we get [(3*3) + 5(3)]/2=(9+15)/2=24/2=12 when n=4, we get [(4*4) + 5(4)]/2=(16+20)/2=36/2=18 when n=5, we get [(5*5) + 5(5)]/2=(25+25)/2=50/2=25 If we want to know the 10th number in this series, we substitute n by 10 in our formula, we get [(10*10) + 5(10)]/2=(100+50)/2=150/2 = 75
arithmetic sequence * * * * * A recursive formula can produce arithmetic, geometric or other sequences. For example, for n = 1, 2, 3, ...: u0 = 2, un = un-1 + 5 is an arithmetic sequence. u0 = 2, un = un-1 * 5 is a geometric sequence. u0 = 0, un = un-1 + n is the sequence of triangular numbers. u0 = 0, un = un-1 + n(n+1)/2 is the sequence of perfect squares. u0 = 1, u1 = 1, un+1 = un-1 + un is the Fibonacci sequence.
The sequence is xn = xn-1 + 2
The answer depends on what the explicit rule is!