10-2x for x = 0, 1, 2, 3, ...
Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is
an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.
The numbers one to ten, in alphabetical order of their names in English.
10
The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)
2n - 12
The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1) = 10*9*8*7/(4*3*2*1) = 210
10
10, 8, 6, 4, 2, 0, -2, -4
10
10
-34
It is negative 2.
16
The answer is 3,840. You multiply the numbers in the sequence by 2, 4, 6, 8, then 10. 1 x 2 = 2 2 x 4 = 8 8 x 6= 48 48 x 8 = 384 384 x 10 = 3,840
Even numbers.
Un = 2n + 2 is one possible answer.
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
It is a number sequence.