0
What is the formula for this sequence 1 1 2 3 4 6 9 13 19 28 41 60 88 129 The pattern is you add the first and third number to get the next and then u add the 2nd a 4th to get the 5th?
Wiki User
∙ 14y ago
Each number in the series is the sum of the preceding number and the number two numbers back from the preceding number.
Xn = Xn-1+Xn-3 where the number that started should be zero.
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
How do you calculate the sum of all numbers from 1 through 100?
The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.
What is the formula for a geometric sequence?
a+a*r+a*r^2+...+a*r^n a = first number r = ratio n = "number of terms"-1
Why are conjectures important in finding unknown terms in a sequence or pattern of numbers?
In order to find the unknown term in a number sequence, you first need to calaculate the advantage of the numbers.
What is the 5th term of the sequence which has a first term of 17?
That depends what the pattern of the sequence is.
What is the nth term formula for the sequence 1 4 9 16 25 36?
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
What is the general pattern of the Fibonacci sequence?
The first number, f1 = 1 The second number, f2 = 1 After that the sequence is defined recursively: fn = fn-1 + fn-2 for n=3, 4, 5, ...
How do you find the 99th term in a sequence?
The formula used to find the 99th term in a sequence is a^n = a^1 + (n-1)d. a^1 is the first term, n is the term number we wish to find, and d is the common difference. In order to find d, the pattern in the sequence must be determined. If the sequence begins 1,4,7,10..., then d=3 because there is a difference of 3 between each number. d can be quite simple or more complicated as it can be a function or formula in of itself. However, in the example, a^1=1, n=99, and d=3. The formula then reads a^99 = 1 + (99-1)3. Therefore, a^99 = 295.
How do you calculate the sum of first 20 prime number?
You find the first 20 prime numbers and add them together. There is no formula for generating a sequence of prime numbers and so none for the series of their sums.You find the first 20 prime numbers and add them together. There is no formula for generating a sequence of prime numbers and so none for the series of their sums.You find the first 20 prime numbers and add them together. There is no formula for generating a sequence of prime numbers and so none for the series of their sums.You find the first 20 prime numbers and add them together. There is no formula for generating a sequence of prime numbers and so none for the series of their sums.
What is the pattern for 1 1 2 3 5 8?
That's a Fibonacci sequence. After the first two numbers, each new number is the sum of the previous two numbers. The next number in that sequence would be 13.
How do you find the next 50nth term in a sequence?
you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given
How do you solve the pattern of 4 9 16 25 36?
This is a sequence based on the squares of numbers (positive integers) but starting with the square of 2. Under normal circumstances the sequence formula would be n2 but as the first term is 4, the sequence formula becomes, (n + 1)2. Check : the third term is (3 + 1)2 = 42 = 16
What is the first 200 odd numbers added together?
You can use the formula for the sum of an arithmetic sequence for this one. The first odd number would presumably be 1; the interval between one number and the next is 2.
