The formula used to find the 99th term in a sequence is a^n = a^1 + (n-1)d. a^1 is the first term, n is the term number we wish to find, and d is the common difference. In order to find d, the pattern in the sequence must be determined. If the sequence begins 1,4,7,10..., then d=3 because there is a difference of 3 between each number. d can be quite simple or more complicated as it can be a function or formula in of itself. However, in the example, a^1=1, n=99, and d=3. The formula then reads a^99 = 1 + (99-1)3. Therefore, a^99 = 295.
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The sequence is just each number is the square of 1 to 5 1 squared is 1 2squared is 4 3squared is 9 ect so the 99th number will be 99 squared which is 9801
You first have to figure out some rule for the sequence. This can be quite tricky.
20th term = 20*(20+1)/2
i dont get it
To find the nth term in a quadratic sequence, we first need to determine the pattern. In this case, the difference between consecutive terms is increasing by 3, 5, 7, 9, and so on. This indicates a quadratic sequence. To find the 9th term, we need to use the formula for the nth term of a quadratic sequence, which is given by: Tn = an^2 + bn + c. By plugging in n=9 and solving for the 9th term, we can find that the 9th term in this quadratic sequence is 74.