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What is the free-fall acceleration in a location where the period of a 0.850 m long pendulum is 1.86 s?
Wiki User
∙ 13y ago
Time period and length of a pendulum are related by:
T = 2(pi)(L).5(g).5
so putting in the values and solving for g yields a result of :
g = 9.70 ms-2
Wiki User
∙ 13y ago
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What are the effects of acceleration due to gravity on the time period of a pendulum?
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
Period of seconds pendulum?
Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2
Is the period of the pendulum influenced by the point from which it is released?
No Time period, T = 2π √(l/g) π - pi l - lenght of the pendulum g - acceleration due to gravity at the place
How do you find time period of pendulum?
T=2π√(L/g)where L is the length of the pendulum and g is the local acceleration of gravity.
Why does accerlation due to gravity affect the period of a pendulum?
The period of a pendulum is give approximately by the formula t = 2*pi*sqrt(l/g) where l is the length of the pendulum and g is the acceleration (not accerlation) due to gravity. Thus g is part of the formula for the period.
How does the period of a pendulum vary?
The period depends only on the acceleration due to gravity and the length of the pendulum. Gravitational acceleration depends on the location on the surface of the earth: latitude, altitude play a part. Also, some pendulums are subject to thermal expansion and so the length changes. These factors do impact on the period of a pendulum.
What are the effects of acceleration due to gravity on the time period of a pendulum?
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
Period of seconds pendulum?
Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2
Does the weight effect the period of a pendulum?
It doesn't. Period depends on the length of the pendulum and the acceleration of gravity. Adding weight doesn't change the period at all.
What are the factors on which the time period of simple pendulum depends?
The length of the pendulum, and the acceleration due to gravity. Despite what many people believe, the mass has nothing to do with the period of a pendulum.
What are two factors that alter the oscillation period of a pendulum?
1. Length of the pendulum 2. acceleration due to gravity at that place
How can pendulum be used to determine local gravitational acceleration?
Measure the length and the period
If a simple pendulum with a period of 1 second is set in motion of the moon what is the new period of this pendulum?
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
Discussion of the measurement of gravity by a bar pendulum?
You can use a simple pendulum, measure how long one period takes, then use the formula for a pendulum, and solve for gravitational acceleration.
What is the length of a pendulum with a period of 4.48ses?
The equation for the length, L, of a pendulum of time period, T, is gievn byL = g(T2/4?2),where g is the acceleration due to gravity. So, for a pendulum of time period 4.48 sec, the length of the pendulum is 4.99 metres (3 s.f).
Is the period of the pendulum influenced by the point from which it is released?
No Time period, T = 2π √(l/g) π - pi l - lenght of the pendulum g - acceleration due to gravity at the place
How do you find time period of pendulum?
T=2π√(L/g)where L is the length of the pendulum and g is the local acceleration of gravity.
