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Q: What is the gcf of 18a times a times b times b and 28times a times a times a times b times b?

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The GCF is 6a2b

The relationship between GCF, LCM, and the numbers aa and bb is: \text{GCF}(a, b) \times \text{LCM}(a, b) = a \times bGCF(a,b)×LCM(a,b)=a×b Given that GCF is 73 and LCM is 1752: \text{GCF}(a, b) \times \text{LCM}(a, b) = a \times bGCF(a,b)×LCM(a,b)=a×b 73 \times 1752 = a \times b73×1752=a×b 127896 = a \times b127896=a×b Now, you'll need to factorize 127896 to find the two numbers that, when multiplied, result in this product. After factorizing, you'll determine which pair of factors satisfies the conditions.

18a^3bc

Answer: GCF= b

b 18a 1.8 doc

The GCF of ba and b is b. That factors to b(a - 1)

GCF of a and b is a if b is divisible by a.87 is divisible by 29 so, GCF(29,87) = 29.

If you have two numbers A and B, and A > B, then GCF(A, B) = (A-B, B) Thus the problem of finding the GCF of A and B has been reduced to finding the GCF of B and a smaller number, A-B. This process can be continued until the two numbers are the same: and that number is the GCF.

The GCF is b.

The GCF is 1.

#include<stdio.h> main() { int a,b,i,lcm,gcf; printf("\n Enter two numbers"); scanf("%d%d",&a,&b); for(i=0;i<=a;i++) { if((b%i==0)&&(a%i==0)) { gcf=i; } } lcm=a*b/gcf; printf("\n GCF is %d and LCM is %d",gcf,lcm); }

To answer that, you'll need to have a numerical value for the letters.