It is: y = mx+b whereas m is the slope and b is the y intercept
The general form of a line written in slope-intercept form is y = mx + b, where m is the slope of the line and b is the y-intercept (the point where the line crosses the y-axis).
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
y=mx + b
The general form is 11x - 10y + 19 = 0
It is x + 3 = 0.
y = 6/7x+3 General form of the line equation: 6x -7y+21 = 0
y = 2x + 1.
General form for a line equation is: y=mx+b.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
Ax+By+C=0
The slope intercept form of the equation of a line is: y = mx + b The general form is: Ax + By + C = 0 So, when the line is given in the slope intercept form, the general form will be mx - y + b = 0
y=mx + b
The general straight line equation is y = mx + c; wher m is the sl;ope a c is the y intersection.Accordingly; y = - 1 1/3 x + 10 1/3 or : 3y = -4x + 31
Answer: y = -2/5x-14/5 which also can be written as 5y = -2x-14 or in the general form of the equation of a straight line as 2x+5y+14 = 0
The general form is 11x - 10y + 19 = 0
The general equation is y = mx + c. m is the slope of the straight line. c is the y intercept. This is readily obtained by putting x = 0 then the general equation simplifies to y = c.
A horizontal line.