To calculate the mass of medication in the solution, multiply the volume of the solution (500 ml) by the concentration of the medication (10%). Convert the percentage to a decimal by dividing by 100 (10% = 0.10). So, 500 ml x 0.10 = 50 grams of medication in 500 ml of a 10% solution.
To make a 3.7% EDTA solution, you would add 3.7 grams of EDTA to 100 mL of solution.
To make a 10 percent solution, you would need to dilute the 50 percent solution by adding 4 ml of solvent to 1 ml of the 50 percent solution. This will result in a total volume of 5 ml with a 10 percent concentration.
There would be 946 mg (2 mg/ml x 473 ml) of active ingredient in 473 ml of the solution. To convert milligrams to grams, divide by 1000, so 946 mg is equal to 0.946 grams in 473 ml of the solution.
To make a 3% solution, you would need 1.5 grams of sugar for every 50 ml of water.
64 (g) / 250 (mL) = 0.256 g/mL = 256 g/L
The water volume is 212,5 mL.
To calculate the mass of medication in the solution, multiply the volume of the solution (500 ml) by the concentration of the medication (10%). Convert the percentage to a decimal by dividing by 100 (10% = 0.10). So, 500 ml x 0.10 = 50 grams of medication in 500 ml of a 10% solution.
To make a 3.7% EDTA solution, you would add 3.7 grams of EDTA to 100 mL of solution.
To make a 0.9% saline solution in 600 ml, you would need 5.4 grams of sodium chloride, as 0.9% of 600 ml is 5.4 ml. The density of sodium chloride is approximately 2.16 grams/ml.
To prepare a 0.100 M solution of trinitrotoluene in 250 ml of solvent, you need 0.025 moles of trinitrotoluene. The molar mass of trinitrotoluene is 227.14 g/mol, so you would need 5.68 grams of trinitrotoluene to make the solution.
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams
To make a 10 percent solution, you would need to dilute the 50 percent solution by adding 4 ml of solvent to 1 ml of the 50 percent solution. This will result in a total volume of 5 ml with a 10 percent concentration.
Is the makeup of the solution expressed as "percent by mass"? If so, to calculate molarity (or normality), you have to also know the density of the solution Step 1. Lets say the solution is 14%, and the density is 1.09 g/mL. We can write the following: (14 grams solute/100 grams solution) (1.09 grams solution/ mL solution) Step 2. Multiplying and cancelling from step 1 gives you 15.26 grams solute / 100 mL solution. Multiplying top and bottom by 10 gives you 152.6 grams solute per liter. Step 3. Molarity is number of moles per liter. Divide the 152.6 grams of the solute by the forumua weight (or molecular weight) of the solute, and you have the number of moles of solute. This number is therefore the molarity of the solution. If the solution is "percent by volume", the number you have is number of grams per 100 mL. Multiply by 10, and you have grams per liter. Then divide by the formula weight, and you have the molarity.
To determine the amount of K2CO3 in a 10% solution, you need to know the total volume of the solution. For example, if you have 1000 mL (1 liter) of the 10% solution, it means there are 100 grams of K2CO3 in that solution. This is because 10% of 1000 mL is 100 grams.
Does not convert; milligrams (mg) and grams (g) are measures of weight or mass and mL (milliliters) is a measure of volume.
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.