answersLogoWhite

0


Best Answer

12.5

User Avatar

Wiki User

12y ago
This answer is:
User Avatar
More answers
User Avatar

AnswerBot

5mo ago

To find the grams in 250 ml of a 5% solution, you can use the formula: (volume in ml * percentage concentration / 100). So for this case: (250 ml * 5%/100) = 12.5 grams.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the grams in 250 ml of a 5 percent solution?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the concentration of a solution consisting of 64 grams of calcium chloride in 250 mL of water?

64 (g) / 250 (mL) = 0.256 g/mL = 256 g/L


How many mL of water are present in 250 mL of a 15 percent by volume aqueous hydrochloric acid solution?

The water volume is 212,5 mL.


How many grams of medication will 500 ml of a 10 percent solution contain?

To calculate the mass of medication in the solution, multiply the volume of the solution (500 ml) by the concentration of the medication (10%). Convert the percentage to a decimal by dividing by 100 (10% = 0.10). So, 500 ml x 0.10 = 50 grams of medication in 500 ml of a 10% solution.


How many grams of EDTA do you add to make a 3.7 percent EDTA solution?

To make a 3.7% EDTA solution, you would add 3.7 grams of EDTA to 100 mL of solution.


How many grams of sodium chloride are needed to prepare 600 ml of a 0.9 percent saline solution?

To make a 0.9% saline solution in 600 ml, you would need 5.4 grams of sodium chloride, as 0.9% of 600 ml is 5.4 ml. The density of sodium chloride is approximately 2.16 grams/ml.


How many grams of the compound trinitrotoluene are needed to prepare 250 ml of a 0.100 M solution of the compound?

To prepare a 0.100 M solution of trinitrotoluene in 250 ml of solvent, you need 0.025 moles of trinitrotoluene. The molar mass of trinitrotoluene is 227.14 g/mol, so you would need 5.68 grams of trinitrotoluene to make the solution.


How many grams of a drug must be used to prepare 2 liters of a 1 percent solution?

1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams


How much solvent must you add to 1 ml of a 50 percent solution to make a 10 percent solution?

To make a 10 percent solution, you would need to dilute the 50 percent solution by adding 4 ml of solvent to 1 ml of the 50 percent solution. This will result in a total volume of 5 ml with a 10 percent concentration.


How do you calculate normality of percent solution?

Is the makeup of the solution expressed as "percent by mass"? If so, to calculate molarity (or normality), you have to also know the density of the solution Step 1. Lets say the solution is 14%, and the density is 1.09 g/mL. We can write the following: (14 grams solute/100 grams solution) (1.09 grams solution/ mL solution) Step 2. Multiplying and cancelling from step 1 gives you 15.26 grams solute / 100 mL solution. Multiplying top and bottom by 10 gives you 152.6 grams solute per liter. Step 3. Molarity is number of moles per liter. Divide the 152.6 grams of the solute by the forumua weight (or molecular weight) of the solute, and you have the number of moles of solute. This number is therefore the molarity of the solution. If the solution is "percent by volume", the number you have is number of grams per 100 mL. Multiply by 10, and you have grams per liter. Then divide by the formula weight, and you have the molarity.


How much K2CO3 in 10 percent solution?

To determine the amount of K2CO3 in a 10% solution, you need to know the total volume of the solution. For example, if you have 1000 mL (1 liter) of the 10% solution, it means there are 100 grams of K2CO3 in that solution. This is because 10% of 1000 mL is 100 grams.


How many grams is 250 ml sugar?

Does not convert; milligrams (mg) and grams (g) are measures of weight or mass and mL (milliliters) is a measure of volume.


How many grams of NaCl are required to prepare 4000 mL of 5 percent solution?

To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.