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Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
A. 2 g
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
dextrose
In a 70% dextrose solution, 70% of the total weight is dextrose. To calculate the grams of dextrose in 400ml of this solution, you would multiply 400ml by 70% (or 0.70) to find the amount of dextrose present.
A 5% dextrose solution is composed of 5 grams of dextrose (glucose) per 100 milliliters of solution. It is commonly used as a source of energy and as a mild hypertonic solution in medical settings.
There are 50 grams of dextrose in a 100 ml solution of dextrose 50%.
To find the number of grams of dextrose in a 1L solution with 5.5% concentration, you can use the formula: mass = volume x concentration. So, for this case, it would be 1L x 5.5% = 55g of dextrose in a 1L solution.
To calculate the amount of dextrose in the IV solution, you first convert 5% w/v to mg/mL. Next, you multiply the concentration by the volume of the IV solution to find the total amount of dextrose in it. For a 475 mL IV solution with 5% w/v dextrose, you would have 475 mL * 5 mg/mL = 2375 mg of dextrose.
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc.A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).Read more: What_does_a_5_percent_sugar_solution_mean
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
50 g
You have 100 grams of pure dextrose and 9 grams of pure sodium chloride added to one liter of distilled water. The solution is sterilized and packed in polypropylene or polyethylene bottles.
D50W solution contains 50g of dextrose per 100ml. Therefore, in 275ml of D50W, there are 137.5g of dextrose present.
The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.
D10W means 10% dextrose in water. 10% dextrose means 10 g per 100 mL. Therefore, there are 50 g in 500 mL of D10W.