Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
A. 2 g
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
A 25 percent glucose solution means that there are 25 grams of glucose in every 100 milliliters of the solution. Therefore, in 25 milliliters of a 25 percent glucose solution, there would be 6.25 grams of glucose. This concentration is commonly used in medical and laboratory settings for various applications.
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
In a 70% dextrose solution, 70% of the total weight is dextrose. To calculate the grams of dextrose in 400ml of this solution, you would multiply 400ml by 70% (or 0.70) to find the amount of dextrose present.
A 5% dextrose solution is composed of 5 grams of dextrose (glucose) per 100 milliliters of solution. It is commonly used as a source of energy and as a mild hypertonic solution in medical settings.
There are 50 grams of dextrose in a 100 ml solution of dextrose 50%.
To find the number of grams of dextrose in a 1L solution with 5.5% concentration, you can use the formula: mass = volume x concentration. So, for this case, it would be 1L x 5.5% = 55g of dextrose in a 1L solution.
23.75 mg of Dextrose is added by intravenous injection of 475 ml of this solution .. wrong!5% WV means 5 grams/100ml ; therefore 23.75 grams/475ml; since there's 1000mg/gramthe number of mg dextrose added by IV injection of 475ml = 23750mg !
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc.A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).Read more: What_does_a_5_percent_sugar_solution_mean
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
50 g
D50W solution contains 50g of dextrose per 100ml. Therefore, in 275ml of D50W, there are 137.5g of dextrose present.
You have 100 grams of pure dextrose and 9 grams of pure sodium chloride added to one liter of distilled water. The solution is sterilized and packed in polypropylene or polyethylene bottles.
The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.
D10W means 10% dextrose in water. 10% dextrose means 10 g per 100 mL. Therefore, there are 50 g in 500 mL of D10W.