The GCF is t.
3
If that's + 7t, the answer is (3t + 5)(2t - 1) If that's - 7t, the answer is (3t - 5)(2t + 1)
(3t + 1)(t + 5)
3 t squared (3t^2)
It's a simple problem in long division and the answer is 2t + 1
3t + 9 = 3(t + 3)
x=y+3t Original formula: y2 -xy = 9t2 -3xt (assumes you meant "9 times t2 " and not (9t)2 ) y2 = xy +9t2 -3xt y2 - 9t2 = xy - 3xt (y-3t)(y+3t) = x(y-3t) (y-3t) = x
It is (3t-2)(3t+2) when factored and it is the difference of two squares
t(ht + 3)
3st + 6tu = 3t (s + 2u)
3(t - 2)(t + 1)
6t2 - 7t - 5 = (3t - 5)*(2t + 1) So (6t2 - 7t - 5)/(3t - 5) = 2t + 1 provided that t is not 5/3