-28
2(5x - 6y)(25x2 + 30xy + 36y2)
6y2+17y-14 = (2x+7)(3x-2) when factored
(y - 6)(y2 + 6y + 36)
It is the product, not the sum, of three consecutive integers that is divisible by 6. The three consecutive integers must be multiplied, not added.For example, 2+3+4 = 9, which is not evenly divisible by 6.If your first number is odd, then the statement works. Here's why:The first number is odd, so it can be written as 2n+1 for some integer n.The next two numbers are just 2n+2 and 2n+3.Then the sum of the three numbers is:(2n+1) + (2n+2) + (2n+3) = 6n + 6which is obviously divisible by 6 regardless of the number you used for n.For the 'Product of three consecutive integers..." see the Related Question below.
6y(1) & 6y(3) The answer is 6y
The GCF is 1.
The GCF is 6y
3
You take out the common factor, 6. 6y + 18 = 6(y + 3)
The greatest common multiple of any set of integers is infinite.
Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)
(6y + 1)(6y - 1)
25x2 - 36y2 = ( 5x + 6y ) ( 5x - 6y )
11
x(y - 10) + 6y
State each expression in terms of its prime or non-numeric factors. 6y = 2 x 3 x y 108 = 2 x 2 x 3 x 3 x 3 The common factors are 2 and 3. The GCF is therefore 2 x 3 = 6.