The divisors of 108 are: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108.
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2(5x - 6y)(25x2 + 30xy + 36y2)
6y2+17y-14 = (2x+7)(3x-2) when factored
(y - 6)(y2 + 6y + 36)
It is the product, not the sum, of three consecutive integers that is divisible by 6. The three consecutive integers must be multiplied, not added.For example, 2+3+4 = 9, which is not evenly divisible by 6.If your first number is odd, then the statement works. Here's why:The first number is odd, so it can be written as 2n+1 for some integer n.The next two numbers are just 2n+2 and 2n+3.Then the sum of the three numbers is:(2n+1) + (2n+2) + (2n+3) = 6n + 6which is obviously divisible by 6 regardless of the number you used for n.For the 'Product of three consecutive integers..." see the Related Question below.