Wiki User
∙ 13y ago71.
(142/2).
Wiki User
∙ 13y ago297 integers, with an average of 5, multiply that to get what their sum was before averaging (=35). Make 6 of the integers 1 to find that greatest possible integer in the list.-Cheers.Actually you make 6 of your integers 1 you would get something else
31
Negative, Zero and Positive is one possible classification.
A positive integer divided by a positive integer always results in a positive quotient. It is not possible to divide by zero.
At least the following families: all integers; all positive integers; all odd integers; and all "square integers", that is, integers that are squares of other integers.
490.
297 integers, with an average of 5, multiply that to get what their sum was before averaging (=35). Make 6 of the integers 1 to find that greatest possible integer in the list.-Cheers.Actually you make 6 of your integers 1 you would get something else
There are 33.
31
Negative, Zero and Positive is one possible classification.
A positive integer divided by a positive integer always results in a positive quotient. It is not possible to divide by zero.
Integers to the nearest hundred, 749.
At least the following families: all integers; all positive integers; all odd integers; and all "square integers", that is, integers that are squares of other integers.
{1,1,47} is the only possible set.
This will work as long as "five" is an acceptable substitute for "several".
12
No, it is not possible.