1*47=47 Only that equation, because 47 is a prime number. >.>
6.02x10^23 multiplied by 9.1x10^23 is equal to: 5.478199999999999 x 10^47
The four consecutive odd integers are 43 + 45 + 47 + 49 = 184
1 x 329, 7 x 47
47 multiplied by 2 would be 94.
1*47=47 Only that equation, because 47 is a prime number. >.>
6.02x10^23 multiplied by 9.1x10^23 is equal to: 5.478199999999999 x 10^47
45 2
The four consecutive odd integers are 43 + 45 + 47 + 49 = 184
31
3x + 6y = 47 6y = -3x + 47 y = -3x/6 + 47/6 y = (-3x + 47)/6 Since we are looking for positive integer, 3x (x > 0) cannot be greater than 47, the possibilities of the numerator are 42, 36, 24, 18, 12, and 6, so that - 3x must be -5, -11, -23, -29, -35, and -41. Since any of them are not multiples of -3, we can not find any pair of positive integers that satisfy the equation. So x and y cannot be both positive integers.
1 x 329, 7 x 47
The least common factor of any set of positive integers is 1.
47 multiplied by 2 would be 94.
The are all two-digit positive integers.
69 * 47 = 3,243
47 × 76 = 3,572