0
The hybridization of N i n N2 is sp.
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
How do you solve n2 equals 20 plus n by factoring?
n2 = 20 + n so n2 - n - 20 = 0 that is (n - 5)(n + 4) = 0 so that n - 5 = 0 or n + 4 = 0 n = 5 or n = -4
What is the first value of n for which n2 plus n plus 41 is not a prime?
n=40 n2+n+41=1681 which is not a prime.
What is the value of n when 6 over n times 5 over n-1 equals 1 over 3 showing all work?
If you mean: 6/n times 5/n-1 = 1/3 Then: 30/n2-n = 1/3 Multiplying both sides by n2-n: 30 = n2-n/3 Multiplying both sides by 3: 90 = n2-n Subtracting 90 from both sides: 0 = n2-n-90 or n2-n-90 = 0 Solving the above quadratic equation: n = -9 or n =10 If n is of a material value its more likely to be 10 Note that n2 means n squared
What is the factor of n2 equals -18-9n?
n2 + 9n + 18 = (n + 6)(n + 3)
N2 plus 11n plus 18 need to writte the expression in factored form?
n2 + 11n + 18 = n2 + 2n + 9n + 18 = n(n+2) + 9(n+2) = (n+9)*(n+2)
What is n2 in math?
n x n = n2
How do you add n squared plus n squared?
n2 + n2 = 2 n2
What is the pmf of trinomial distribution?
P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n
What hybridization would you expect for the C and N atoms in urea according to the VSEPR model?
C = sp^2 hybridization N = sp^3 hybridization
What is Factor 0.04m2 - n2?
.04m2-n2=(.2m+n)(.2m-n)
What is the slowest in sorting algorithm?
There are many sorting algorithms with worst case of complexity O(n2). These algorithms have different average and best cases. They are:Best caseAverage caseWorst case1) Quick sortO(n*log n)O(n*log n)O(n2)2) Insertion sortO(n)O(n2)O(n2)3) Bubble sortO(n)O(n2)O(n2)4) Selection sortO(n2)O(n2)O(n2)
What is n times n?
n2
How do you solve n2 equals 20 plus n by factoring?
n2 = 20 + n so n2 - n - 20 = 0 that is (n - 5)(n + 4) = 0 so that n - 5 = 0 or n + 4 = 0 n = 5 or n = -4
What is the first value of n for which n2 plus n plus 41 is not a prime?
n=40 n2+n+41=1681 which is not a prime.
Are there infinitely many primes of the form n2-1 and n2-2 and n2-3 and n2-4?
n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.
What is the value of n when 6 over n times 5 over n-1 equals 1 over 3 showing all work?
If you mean: 6/n times 5/n-1 = 1/3 Then: 30/n2-n = 1/3 Multiplying both sides by n2-n: 30 = n2-n/3 Multiplying both sides by 3: 90 = n2-n Subtracting 90 from both sides: 0 = n2-n-90 or n2-n-90 = 0 Solving the above quadratic equation: n = -9 or n =10 If n is of a material value its more likely to be 10 Note that n2 means n squared
What is the factor of n2 equals -18-9n?
n2 + 9n + 18 = (n + 6)(n + 3)
