.04m2-n2=(.2m+n)(.2m-n)
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(n - 10)(n + 4)
-n(n + 10) or n(-n - 10)
5(n2 + 2n + 4)
Take 5 out. If the missing signs are pluses, it becomes 5(n2 + 2n + 4) If the missing signs are minuses, it becomes 5(n2 - 2n - 4)
n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.