If: n2 = 19 Then: n = the square root of 19.
n2 = 10n + 56 Subtract (10n + 56) from each side: n2 - 10n - 56 = 0 Now you have something on the left side that you can factor: (n - 14) (n + 4) = 0 n = +14 n = - 4
n2 + 7n - 44 (n + 11)(n - 4)
n x n2 = n3
Endothermic
(n + 4)(n - 4)
-mn(m - n2)(m + n2)
If: n2 = 19 Then: n = the square root of 19.
.04m2-n2=(.2m+n)(.2m-n)
Conditional statement: If n2 equals 64, then n equals 8, where n2 equals 64 is the hypothesis, and n equals 8 is the conclusion. In order to obtain the converse of the conditional we reverse the 2 clauses, then the original conclusion becomes the new hypothesis and the original hypothesis becomes the new conclusion. So that, Converse: If n equals 8, then n2 equals 64.
N2
Oh, dude, balancing chemical equations, like, totally takes me back to high school chemistry. So, like, to balance Ag + N2 = Ag3N, you gotta make sure the number of each type of atom is the same on both sides. Start by putting a 3 in front of Ag on the left to match the Ag3N on the right, then add a 2 in front of N2 to balance the nitrogen atoms. Voilà! Balanced equation, like, no big deal.
N2 its an element in its natural state
n2 - 10n + 21 = 0 Two numbers that sum to -10 and multiply to 21 are -3 and -7 So (n - 3)*(n - 7) = 0
n20
n2 = 10n + 56 Subtract (10n + 56) from each side: n2 - 10n - 56 = 0 Now you have something on the left side that you can factor: (n - 14) (n + 4) = 0 n = +14 n = - 4
If you mean: n2+16n+64 then it is (n+8)(n+8) when factored