Use the Pythagorean theorem.
a2 + b2 = c2
a and b are legs and c is the hypotenuse
c2 = a2 + b2
c = sqrt(a2 + b2) [No +/- as the answer must be positive]
c = sqrt(52 + 132)
c = sqrt(25 + 169)
c = sqrt(194)
c = 13.9
---------------------13.9 is the hypotenuse, but 14 may do as well
No because the hypotenuse is used to show which line is the longest in the triangle therefore it will always be the longest.
"Hypotenuse-Leg" is a short-hand label for a corollary that you can use to prove that two right triangles are congruent. In general, in order to prove that two triangles are congruent, you have to show that either (two sides and the included angle) or (two angles and the included side) of one triangle are equal to the corresponding parts of the other one. But if you're dealing with two right triangles, it's enough to show that the hypotenuse and one leg of the the first triangle are equal to the hypotenuse and leg of the other one, and then you can say that the triangles are congruent. This process is called "Hypotenuse-Leg".
Because Corresponding Parts of Congruent Triangles, there are five ways to prove that two triangles are congruent. Show that all sides are congruent. (SSS) Show that two sides and their common angle are congruent. (SAS) Show that two angles and their common side are congruent. (ASA) Show that two angles and one of the non common sides are congruent. (AAS) Show that the hypotenuse and one leg of a right triangle are congruent. (HL)
All right triangles inscribed in a circle have their vertices on the circle and the hypotenuse as the circle's diameter. Thus the midpoint of the hypotenuse is the center of the circle nd all points on the circle are eqully as far from the center even so the vertex of the right angle.
A Cut the legs off of this A and you have a triangle, which is a polygon. Triangle Heptagon Quadrilateral Pentagon Hexagon Octagon Decagon Nonagon that is all of the polygons
the only way for a right triangle to have a line of symmetry, is if the legs of the triangle are congruent. Or you can show that both non-right angles are congruent (45 degrees). you may also prove that the altitude of the triangle bisects the hypotenuse or that it equals 1/2 of the hypotenuse.
No because the hypotenuse is used to show which line is the longest in the triangle therefore it will always be the longest.
"Hypotenuse-Leg" is a short-hand label for a corollary that you can use to prove that two right triangles are congruent. In general, in order to prove that two triangles are congruent, you have to show that either (two sides and the included angle) or (two angles and the included side) of one triangle are equal to the corresponding parts of the other one. But if you're dealing with two right triangles, it's enough to show that the hypotenuse and one leg of the the first triangle are equal to the hypotenuse and leg of the other one, and then you can say that the triangles are congruent. This process is called "Hypotenuse-Leg".
Because Corresponding Parts of Congruent Triangles, there are five ways to prove that two triangles are congruent. Show that all sides are congruent. (SSS) Show that two sides and their common angle are congruent. (SAS) Show that two angles and their common side are congruent. (ASA) Show that two angles and one of the non common sides are congruent. (AAS) Show that the hypotenuse and one leg of a right triangle are congruent. (HL)
The area is about 71.20 square units. (71.203932)If you had to show how to calculate this, it is using Pythagoras' theoremand the area of a triangle:a2 + b2 = c2 (hypotenuse)x2 + 132 = 172x2 + 169 = 289x2 = 120x = about 10.9544A = 1/2 B x HA = 1/2 (13 x 10.9544)A = 142.4038 / 2A = 71.2039
All right triangles inscribed in a circle have their vertices on the circle and the hypotenuse as the circle's diameter. Thus the midpoint of the hypotenuse is the center of the circle nd all points on the circle are eqully as far from the center even so the vertex of the right angle.
This is not possible. If a triangle is a Right angled triangle then the sum of the two angles which are not right will be = 90 [Angle Sum Property] That's why you see.
One of its interior will be 90 degrees. also there will be a little box in the corner to show that it is a right angle.
A Cut the legs off of this A and you have a triangle, which is a polygon. Triangle Heptagon Quadrilateral Pentagon Hexagon Octagon Decagon Nonagon that is all of the polygons
the pathagoream theorem is the key to finding a missing length of a side of a right triangle. it is a2+b2=c2. c always stands for the hypotenuse, or the side opposite of the right angle. a and b stand for the legs, or the sides that come together to make the right angle.now for an examplesay you have a triangle without a length for the hypotenuse. you take the formula, a2+b2=c2 and replace a and bwith the length of the legs, say 4in. and 8in. the formula is now either 42+82=c2, or 82+42=c2. it doesnt matter. now you square the legs and the formula becomes 16+64=c2. add them together and you get 80=c2. now you square root it so that you have c and not c2. and the square root of 80 is 8.94427190999916. sorry about the big decimal. we round it up at my school to the nearest tenth so now your answer would be 9.0=c.be absolutely sure to put 9.0 instead of 9 to show youre rounding to the tenthi hope i helped even though it was really long
yes, just type scalene triangle in Google Image search.
If there is a picture, it would be very useful, because the height and slant height are two sides of a right triangle. A good picture would show that the bottom side of this triangle is half the side length of the square. This is a leg of the right triangle: A=12' The hypotenuse of the triangle is the slant height: C=46' The "unknown" height is the other leg of the right triangle: B=? The pythagorean theorem A2+B2=C2 gives 144sqft+B2=2116sqft Solving for B gives B=44.4' Therefore, the height of the pyramid is 44.4 feet.