This is not possible. If a triangle is a Right angled triangle then the sum of the two angles which are not right will be = 90 [Angle Sum Property] That's why you see.
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Without seeing the picture, I can't tell what's already known to be congruent, so there's no way I can figure out what 'else' is needed.
Two lines that form a right angle are Perpendicular. This can be show by an upside down T.
256 to get this answer you times it if your teacher is one of those who like to show your work it should look like this A=b(h) A=32(8) A=256
A Scalene Triangle is a triangle where all three sides are different in length.
This is not possible. If a triangle is a Right angled triangle then the sum of the two angles which are not right will be = 90 [Angle Sum Property] That's why you see.
Equilateral TriangleIsosceles TriangleRight Angled TriangleScalene Triangle
I won't explain it in depth but the simple answer is because if you take and identical right triangle then you can arrange them to make a rectangle. I've attached a link to an animation showing it rearranging a triangle to show the relationship.
A scalene acute triangle is a triangle with all sides of different lengths and all angles less than 90 degrees. It does not have any equal sides or equal angles. Therefore, a picture of a scalene acute triangle would show three lines of different lengths connecting to form a triangle with three angles less than 90 degrees.
Cannot show a picture, but visualise a right angled triangle. Then imagine one of the [acute] vertices chopped off by a line parallel to the opposite side. You will then have a trapezium with two right angles. Very crudely, it should look like the figure below: ---\ |__\
Yes, it's quite simple. First, let's define what a scalene obtuse triangle is and in so doing show that a scalene obtuse triangle CAN be constructed.'Scalene' means that all three sides are not equal (of different lengths).'Obtuse' means that at least one of the angles is greater than (>) 90o.So, as long as the triangle has 3 sides that are not equal and contains one angle that is >90o, you can create a scalene obtuse triangle.Another way to make sure you can construct the aforementioned is:If you know the lengths of the triagle sides you can add any two(2) of them the sum of which should be greater than the length of the 3rd side. This is know as the Triangle Inequality Theorem.Under the Resources link, there is a website to construct a scalene obtuse triangle as proof.
And Equilateral Triangle has three EQUAL sides. Basically just your ordinary triangle. The Isosceles triangle usually has TWO equal sides, and one odd side,( not the same size in degrees.) A scalene Triangle also has TWO of the same sides, BUT- Its degrees are usually always different. I'll show you some examples. The first example below is an isosceles Triangle. The 2nd is the Scalene Triangle... Hope I helped...
the only way for a right triangle to have a line of symmetry, is if the legs of the triangle are congruent. Or you can show that both non-right angles are congruent (45 degrees). you may also prove that the altitude of the triangle bisects the hypotenuse or that it equals 1/2 of the hypotenuse.
One of its interior will be 90 degrees. also there will be a little box in the corner to show that it is a right angle.
The answer depends on how sine and cosine are defined: as ratios in right angled triangles, as infinite series or some other way (there are many). The explanation is easiest for definitions based on right angled triangles. Since this browser does not allow graphics, the explanation will be simpler to follow if you just sketch a rough triangle. Suppose you have triangle ABC which is right angled at C. Then, since angle A + angle B + angle C = 180 degrees, angle A + angle B = 90 deg. That is, A and B are complementary angles. Now consider the ratio of the sides BC/AB. AB is the hypotenuse of the triangle. From the perspective of angle A, BC is the opposite side so the above ratio is sin(A). From the perspective of angle B, BC is the adjacent side so the above ratio is cos(B). Thus sin(A) = cos(B). Similarly, if you consider AC/AB you can show that cos(A) = sin(B).
You can use the distance formula to show that all four sides are the same length. The shape must, therefore, be a rhombus or square. If you then show that the length of the diagonal is sqrt(2) times the length of the side then, by Pythagoras, the diagonal and sides from a right angled triangle. The shape must, therefore, be a square.