In order to compute that integral, we need to use the power rule:
∫ xⁿ dx = xn + 1/(n + 1) + c where n is any constant except 0 and -1.
Apply that rule to get:
∫ 3x dx
= 3 ∫ x dx [Factor out the constant]
= 3 ∫ x1 dx [Make note of the exponent]
= 3x1 + 1/(1 + 1) + c
= 3x2/2 + c
So that is the integral of 3x.
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∫ xⁿ dx = xn + 1/(n + 1) + c where n is any constant except 0 and -1.
Apply that rule to get:
∫ 3x dx
= 3 ∫ x dx [Factor out the constant]
= 3 ∫ x1 dx [Make note of the exponent]