dy/dx = 3
integral = (3x^2)/2
3x - y = 4 Get y by itself to see if it is the same as y = 3x - 4: 3x = 4 + y 3x - 4 = y Therefore, 3x - y = 4 is the equivalent of y = 3x - 4.
y = 2 sin 3x y' = 2(sin 3x)'(3x)' y' = 2(cos 3x)(3) y' = 6 cos 3x
3x - y = -1 x = -2 3(-2) -y = -1 -6 - y = -1 -y = 5 y = -5
5x2y = 3x - 6y 5x2y + 6y = 3x y(5x2 + 6) = 3x y = (3x)/(5x2 + 6) This is a rational function.
3x+y=-1 y=-1-3x5x-y=9 5x-(-1-3x)=95x+1+3x=98x=8x=1y=-1-3(1)y=-4(1,-4)
3x - y = 4 Get y by itself to see if it is the same as y = 3x - 4: 3x = 4 + y 3x - 4 = y Therefore, 3x - y = 4 is the equivalent of y = 3x - 4.
y = 15 (by transitivity)
Well, if 3x equals 12, then x equals 4. And if y equals 3x, then y equals 3 times 4, which is 12. So, y equals 12. Math can be a piece of cake when you break it down like that!
-9
3x-y=9 y=3x-9
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
y equals 3x has the greater slope.
Their graphs are.
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
3x - y = 12 is the same as 3x - 12 = y, or y = 3x - 12.
Slope=3, y-intercept=0. y=3x or y=3x+0
A pair of simultaneous eq;ns. 3x + y = 4 x + y = 0 Subtract the two eq'ns. This will eliminate 'y' 2x = 4 x = 2 Substitute this value of 'x' into either eq'n for 'y' 2 + y = 0 y = -2 or 3)2) + y = 4 6 + y = 4 y = 4 - 6 y = -2 ( again) . So the answer is ( x,y) = ( 2, -2).