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What else can I help you with?
What is the integral of expx2?
X^2? 1/3x^3
What is the integral of 3 x square?
Int = 3x^(2) dy y = 3x^(3) / 3 + c y = x^(3) + C
What is the indefinite answer of 3(3x-1)4 dx?
To find the indefinite integral of the expression (3(3x-1)^4 , dx), we can use the power rule of integration. First, we can factor out the constant 3, then apply the substitution method or directly integrate. The integral becomes: [ \int 3(3x-1)^4 , dx = 3 \cdot \frac{(3x-1)^5}{15} + C = \frac{(3x-1)^5}{5} + C, ] where (C) is the constant of integration.
How do you integrate a number in respect to x?
multiply the number times x. For example, the integral of 3 is 3x.
What is the integral of 2x square plus 4x minus 3 divided by x plus 2?
If you mean integral[(2x^2 +4x -3)(x+2)], then multiply them out to get: Integral[2x^3+8x^2+5x-6]. This is then easy to solve and is = 2/4x^4+8/3x^3+5/2x^2-6x +c
Integral of -3 dx?
-3x
Integral of 3 raised to x?
The integral of 3x is ln(3)*3x. Take the natural log of the base and multiply it by the base raised to the power.
What is the integral of -3dx?
∫(-3)dx = -3x + C
What is the integral of expx2?
X^2? 1/3x^3
How do you Differentiate and Integrate y equals 3x?
dy/dx = 3 integral = (3x^2)/2
What is integral of xe3x?
(3x-1) * exp(3*x) / 9
What is the integral of 3 x square?
Int = 3x^(2) dy y = 3x^(3) / 3 + c y = x^(3) + C
Integral of 3x-2 dx?
5
What is the indefinite answer of 3(3x-1)4 dx?
To find the indefinite integral of the expression (3(3x-1)^4 , dx), we can use the power rule of integration. First, we can factor out the constant 3, then apply the substitution method or directly integrate. The integral becomes: [ \int 3(3x-1)^4 , dx = 3 \cdot \frac{(3x-1)^5}{15} + C = \frac{(3x-1)^5}{5} + C, ] where (C) is the constant of integration.
How do you integrate a number in respect to x?
multiply the number times x. For example, the integral of 3 is 3x.
What is the integral of 3sin3x?
-cos(3x) + constant
Can 3x-4 be simplified?
7
