∫ 1/sin(x) dx = ln(tan(x/2)) + C
C is the constant of integration.
∫ 1/sinh2(x) dx = -cotanh + C C is the constant of integration.
∫ 1/sin2(x) dx = -cot(x) + CC is the constant of integration.
∫ 1/sinh(x) dx = ln(tanh(x/2)) + C C is the constant of integration.
if you are integrating with respect to x, the indefinite integral of 1 is just x
∫ (1/x) dx = ln(x) + C C is the constant of integration.
∫ 1/cos2(x) dx = tan(x) + C C is the constant of integration.
It is 1.
I will assume that this is sopposed to be integrated with respect to x. To make this problem easier, imagine that the integrand is x raised to the negative 3. The integral is 1/(-2x-2) plus some constant c.
2
∫ 1/cosh2(x) dx = tanh(x) + C C is the constant of integration.
There can be no definite integral because the limits of integration are not specified. The indefinite integral of 1/x2 is -1/x + C
0.5