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∫ (1/x) dx = ln(x) + C

C is the constant of integration.

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โˆ™ 2010-11-05 03:53:05
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A polynomial of degree zero is a constant term

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Q: What is the integral of 1 divided by x with respect to x?
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Related questions

What you the integral of 1?

if you are integrating with respect to x, the indefinite integral of 1 is just x


What is the integral of 1 divided by the cosine squared of x with respect to x?

∫ 1/cos2(x) dx = tan(x) + C C is the constant of integration.


What is the integral of 1 divided by the square of the hyperbolic sine of x with respect to x?

∫ 1/sinh2(x) dx = -cotanh + C C is the constant of integration.


What is the integral of 1 divided by the sine squared of x with respect to x?

∫ 1/sin2(x) dx = -cot(x) + CC is the constant of integration.


What is the integral of 1 divided by the sine of x with respect to x?

∫ 1/sin(x) dx = ln(tan(x/2)) + C C is the constant of integration.


What is the integral of 1 divided by the square of the hyperbolic cosine of x with respect to x?

∫ 1/cosh2(x) dx = tanh(x) + C C is the constant of integration.


What is the integral of 1 divided by the cosine of x with respect to x?

∫ 1/cos(x) dx = ln(sec(x) + tan(x)) + C C is the constant of integration.


What is the integral of 1 divided by x squared?

The indefinite integral of (1/x^2)*dx is -1/x+C.


What is the integral of 1 divided by the hyperbolic sine of x with respect to x?

∫ 1/sinh(x) dx = ln(tanh(x/2)) + C C is the constant of integration.


What is the integral of 1 divided by the quantity 1 plus the square of x with respect to x?

2


Integral of 1 divided by x cubed?

I will assume that this is sopposed to be integrated with respect to x. To make this problem easier, imagine that the integrand is x raised to the negative 3. The integral is 1/(-2x-2) plus some constant c.


What is the integral of f divided by the quantity 1 minus f with respect to x where f is a function of x?

∫ f(x)/(1 - f(x)) dx = -x + ∫ 1/(1 - f(x)) dx

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