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∫ (1/x) dx = ln(x) + C
C is the constant of integration.
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∙ 13y ago
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What you the integral of 1?
if you are integrating with respect to x, the indefinite integral of 1 is just x
What is the integral of 1 divided by the cosine squared of x with respect to x?
∫ 1/cos2(x) dx = tan(x) + C C is the constant of integration.
What is the integral of 1 divided by the square of the hyperbolic sine of x with respect to x?
∫ 1/sinh2(x) dx = -cotanh + C C is the constant of integration.
What is the integral of 1 divided by the sine squared of x with respect to x?
∫ 1/sin2(x) dx = -cot(x) + CC is the constant of integration.
What is the integral of 1 divided by the sine of x with respect to x?
∫ 1/sin(x) dx = ln(tan(x/2)) + C C is the constant of integration.
What is the integral of 1 divided by the square of the hyperbolic cosine of x with respect to x?
∫ 1/cosh2(x) dx = tanh(x) + C C is the constant of integration.
What is the integral of 1 divided by the cosine of x with respect to x?
∫ 1/cos(x) dx = ln(sec(x) + tan(x)) + C C is the constant of integration.
What is the integral of 1 divided by the hyperbolic sine of x with respect to x?
∫ 1/sinh(x) dx = ln(tanh(x/2)) + C C is the constant of integration.
What is the integral of 1 divided by the quantity 1 plus the square of x with respect to x?
2
Integral of 1 divided by x cubed?
I will assume that this is sopposed to be integrated with respect to x. To make this problem easier, imagine that the integrand is x raised to the negative 3. The integral is 1/(-2x-2) plus some constant c.
What is the integral of 1 divided by x squared?
The indefinite integral of (1/x^2)*dx is -1/x+C.
What is the integral of f divided by the quantity 1 minus f with respect to x where f is a function of x?
∫ f(x)/(1 - f(x)) dx = -x + ∫ 1/(1 - f(x)) dx
