1.001
∫ 1/cos(x) dx = ln(sec(x) + tan(x)) + C C is the constant of integration.
(ex)3=e3x, so int[(ex)3dx]=int[e3xdx]=e3x/3 the integral ex^3 involves a complex function useful only to integrations such as this known as the exponential integral, or En(x). The integral is:-(1/3)x*E2/3(-x3). To solve this integral, and for more information on the exponential integral, go to http://integrals.wolfram.com/index.jsp?expr=e^(x^3)&random=false
The integral of arcsin(x) dx is x arcsin(x) + (1-x2)1/2 + C.
x
The integral of cosine cubed is sinx- 1/3 sin cubed x + c
1/x2
The indefinite integral of (1/x^2)*dx is -1/x+C.
x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,
-(x-1)-1 or -1/(x-1)
0.5
4x cubed y cubed z divided by x negative squared y negative 1 z sqaured = 4
3
0.5
Integral of [1/(sin x cos x) dx] (substitute sin2 x + cos2 x for 1)= Integral of [(sin2 x + cos2 x)/(sin x cos x) dx]= Integral of [sin2 x/(sin x cos x) dx] + Integral of [cos2 x/(sin x cos x) dx]= Integral of (sin x/cos x dx) + Integral of (cos x/sin x dx)= Integral of tan x dx + Integral of cot x dx= ln |sec x| + ln |sin x| + C
∫ (1/x) dx = ln(x) + C C is the constant of integration.
1.001