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Q: What is the integral of e to the power of x with respect to x?

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integral of e to the power -x is -e to the power -x

The antiderivative, or indefinite integral, of ex, is ex + C.

if you mean e to the x power times log of x, it is e to the x divided by x

The integral of X 4Y X 8Y 2 With respect to X is 2ln(10/9).

if you are integrating with respect to x, the indefinite integral of 1 is just x

Use integration by parts. integral of xe^xdx =xe^x-integral of e^xdx. This is xe^x-e^x +C. Check by differentiating. We get x(e^x)+e^x(1)-e^x, which equals xe^x. That's it!

âˆ« ax dx = ax/ln(a) + C C is the constant of integration.

Writing equations in questions is problematic - some symbols regularly get eliminated.The integral of e to the power x is: e to the power x + C If your expression contains no variables, for example e times e, or e to the power e, then the entire expression is a constant; in this case, the integral is this constant times x + C.

d/dx âˆ« f(x) dx = f(x)

I'm not sure if you mean e^x + 17 or e^(x+17) so we'll do both. First, the integral of e^x + 17 because these terms are being added you can integrate them separately: integral((e^x)dx) + integral(17dx) integral of e^x is just e^x + C Integral of 17 is 17x + C, so we get: e^x + 17x + C Second, the integral of e^(x+17) we know how to integrate the form e^u, so just do a u substitution u=x+17 du=dx so we get integral((e^u)du)=e^u + C resubstitute for u and get e^(x+17) + C

With respect to x, this integral is (-15/2) cos2x + C.

x=1

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