-logx=21.1 logx=-21.1 e^-21.1=x
logx = 2 so x = 10logx = 102 = 100 ie x = 100.
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3
You can't solve this since it isn't an equation.There is also an ambiguity (it's hard to write math on a typewriter keyboard) - are we talking about log(x3) or maybe logx(3)?Restate the question: Simplify log(x3)Answer: 3log(x)You could explain this by saying: log(x3) = log[(x)(x)(x)] = logx + logx + logx = 3logx. The general rule is log(xn) = nlogx.
Assuming base 10. 100.38 = X = 2.398832919 ===========
The antiderivative, or indefinite integral, of ex, is ex + C.
X(logX-1) + C
logx^3logx^2log14 is 3logx2logxlog14 this equals 6 log14 (logx)^2 So for example, if y=6log14(logx)^2 the log x = square root of (y/6(log14))
logx^2=2 2logx=2 logx=1 10^1=x x=10
y=logx y=10 logx= 10 10logx = 10log1 logx = log1 x = 1 //NajN
log(100x) can be written as log100 + logx. This =2+logx
(ex)3=e3x, so int[(ex)3dx]=int[e3xdx]=e3x/3 the integral ex^3 involves a complex function useful only to integrations such as this known as the exponential integral, or En(x). The integral is:-(1/3)x*E2/3(-x3). To solve this integral, and for more information on the exponential integral, go to http://integrals.wolfram.com/index.jsp?expr=e^(x^3)&random=false
The derivative of logx, assuming base 10, is 1/(xln10).
-logx=21.1 logx=-21.1 e^-21.1=x
∫ ex dx = ex + CC is the constant of integration.
logx = 2 so x = 10logx = 102 = 100 ie x = 100.
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3