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Q: What is the integral of X 4Y X 8Y 2 With respect to X?

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4y + 8y = 12y 4y - 8y = -4y 4y x 8y = 32y2 4y/8y = 1/2

14

y2 + 8y + 16 = y2 + 4y + 4y + 16 = y(y + 4) + 4(y + 4) = (y + 4)(y + 4) or (y + 4)2

-2

7 + 8y - 3y + 2 =7 + 2 + 8y - 3y = 9 + 8y - 3y = 9 + 5y

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4y + 8y = 12y 4y - 8y = -4y 4y x 8y = 32y2 4y/8y = 1/2

2x + 8y --- has a GCF of 2= 2(x + 4y)

12y-7

14

( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer

8me+8you because 4y2 = 2(4y) = 8y

2 - 8y + 6 = 4y - 702 + 6 + 70 = 4y + 8y78 = 12yy = 78/12y = 6.5

Equations: x = 2 -2y and x^2 +4y^2 = 4 If: x = 2 -2y Then: x^2 = 4y^2 -8y +4 If: x^2 +4y^2 = 4 Then: 4y^2 -8y +4 +4y^2 = 4 Collecting and transposing terms: 8y^2 -8y = 0 or y^2 -y = 0 Factorizing the above: (y-1)(y+0) = 0 meaning y = 1 or 0 By substitution points of contact are made at: (0, 1) and (2, 0)

3x - 4y = 8Solve for x:3x = 4y + 8x = 4/3y + 8/3Solve for y:-4y = -3x + 8y = 3/4x - 2

6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2

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3x - 4y = 8Solve for x:3x = 4y + 8x = 4/3y + 8/3Solve for y:-4y = -3x + 8y = 3/4x - 2

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