Top Answer

sin2 x = 1/2(1 - cos 2x)

⇒ ∫sin2 x = ∫1/2(1 - cos 2x)

= x/2 - 1/4 sin 2x + c

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0🤨

0😮

0😂

0.5(x-sin(x)cos(x))+c

-cosine x

Ã¢Ë†Â« 1/sin2(x) dx = -cot(x) + CC is the constant of integration.

âˆ« sin(x)/cos2(x) dx = sec(x) + C C is the constant of integration.

âˆ« cos(x)/sin2(x) dx = -cosec(x) + C C is the constant of integration.

-cotan(x)

integral of radical sinx

6,561 (i solved it by using this sentence: (9x9) x (9x9)= 81x81=6,561

Answer 1 Put simply, sine squared is sinX x sinX. However, sine is a function, so the real question must be 'what is sinx squared' or 'what is sin squared x': 'Sin(x) squared' would be sin(x^2), i.e. the 'x' is squared before performing the function sin. 'Sin squared x' would be sin^2(x) i.e. sin squared times sin squared: sin(x) x sin(x). This can also be written as (sinx)^2 but means exactly the same. Answer 2 Sine squared is sin^2(x). If the power was placed like this sin(x)^2, then the X is what is being squared. If it's sin^2(x) it's telling you they want sin(x) times sin(x).

The indefinite integral of (1/x^2)*dx is -1/x+C.

arctan(x)

maths signs

the integral of the square-root of (x-1)2 = x2/2 - x + C

There can be no definite integral because the limits of integration are not specified. The indefinite integral of 1/x2 is -1/x + C

âˆ« sin(x) dx = -cos(x) + CC is the constant of integration.

âˆ« sinh(x) dx = cosh(x) + C C is the constant of integration.

tan(sqrtX) + C

Cosine squared theta = 1 + Sine squared theta

(x+sinxcosx)/2, can do it by parts or by knowing your double angle formulas

No, they do not.

3

ln(sinx) + 1/3ln(sin3x) + C

Your question is insufficiently precise, but I'll try to answer anyway. "Sine squared theta" usually means "the value of the sine of theta, quantity squared". "Sine theta squared" usually means "the value of the sine of the quantity theta*theta". The two are not at all the same.

Trying to integrate: cos2x sin x dx Substitute y = cos x Then dy = -sin x dx So the integral becomes: -y2dy Integrating gives -1/3 y3 Substituting back: -1/3 cos3x

(1 - cos(2x))/2, where x is the variable. And/Or, 1 - cos(x)^2, where x is the variable.

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