S sqrt(X - 1)/x dx
this, I think, can be rewritten as..............
S (X - 1)^1/2 * 1/X dx
2/3(X -1)^3/2 * ln(X) + C
2/3ln(X)/sqrt[(X -1)^3] + C
No, it is not even a real number. It is an imaginary number.
Yes, work is the integral of force over a distance.
It is the integral over the (perpendicular) autocorrelation function.
The integral of motion in classical mechanics is significant because it represents a conserved quantity that remains constant throughout the motion of a system. This allows us to simplify the analysis of complex systems by providing a way to predict and understand their behavior over time.
x/sqrt(x)=sqrt(x) integral sqrt(x)=2/3x3/2
Pressure is a measure of force applied over a specific area. It is usually measured in units such as pounds per square inch (psi) or pascals (Pa). The quantity of pressure can vary depending on the force applied and the area over which it is distributed.
The first integral of motion in classical mechanics is significant because it represents a conserved quantity in a system, meaning it remains constant over time. This conservation law helps simplify the analysis of complex systems and provides insights into the behavior of particles and objects in motion.
Negative numbers cannot be rooted. As it can be seen on a calculator when -25 is rooted is says error. Only positive numbers can be rooted. If it resulted in a negative try going over the problem.
The 3s would cancel and it would become the integral of 1/x which is ln x.
To determine if a wavefunction is normalized, you need to calculate the integral of the absolute square of the wavefunction over all space. If the result is equal to 1, then the wavefunction is normalized.
ln |x|+C is the answer
The "s" on top of an "s" symbol is typically used in mathematics to represent integration and is called the integral symbol. It is used to denote the process of finding the area under a curve or the accumulation of a quantity over an interval.