Let the middle one be n, then:
(n - 2)(n + 2) = 3n + 6
→ n² - 4 = 3n + 6
→ n² - 3n - 10 = 0
→ (n + 2)(n - 5) = 0
→ n = -2 or 5
-2 can be discounted as n is odd
→ n = 5
→ largest of the three odd numbers is 5 + 2 = 7.
-1
56.25% is not an integer and so cannot be expressed as a sum, difference, product or quotient of consecutive integers.
Yes, the integers are 12 and 13.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
The integers are 5 and 7.
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
The integers are 47, 49, 51, and 53. 47 * 53 = 2491
One possible answer is -4 and -3.
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
10-11-12
9240 is the product of the three consecutive integers 20, 21, and 22.
Consecutive odd integers would be 5 and 7.