The last prime before 400 is 397.The prime factorization of 400 is 2x2x2x2x5x5.
Yes. Since 7 is a prime number, you have found all the prime numbers, with 7 being the final prime factor.
Prime factorization is dividing a number by prime numbers (starting with 2) until you reach a final, last number (has to be a prime number. So 670 = 2 x 5 x 67. In this case there is no repetition of any number, thus there is no need for exponents.
406=2x203203=7x29PF=2x7x29The PF (Prime Factorization) of 406 is 2x7x29.*NOTE: When solving prime factorization, please use a factor tree. They're useful because when you start with a number, you find two factors that together multiplied equal the top number. If one of those factors are composite, find two factors for that number, and keep going until you come to a conclusion where the last number is prime. Therefore, the first factor for each composite factor of the top number, multiplied together, equal the number you started with.
No.Two reasons that are easy to spot:940 is an even number and the only even prime number is 2;the last digit of 940 is 0 and so it is divisible by 10.The prime factorization of 940 is 2 x 2 x 5 x 47
No, there is no last prime number. They go on forever.
its easy to tell that if the last number ends with 0,2,4,6,8,10,12,14,16,18,20 so on and so on then its even if the answer starts with a 1,3,5,7,9,11,13,15,17,19 so on so on then its an odd number
Because if all the factors are prime, the factorization can't be broken down further. Consider some factor strings for 210: 2 x 105 2 x 3 x 35 2 x 3 x 5 x 7 The last (and longest) is the prime factorization.
The last prime number before 50 is 47.
The is no last prime number - unless you are counting down, in which case, it is 2.
The last prime number before 100 is 97
There is no last prime number: they go on for ever. The first prime larger than 100 is 101.