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18cm is the area and perimeter. the width is 3cm.
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
Width of rectangle: 144/18 = 8cm Perimeter of rectangle: 2*(18+8) = 52cm
If that's its length and width then perimeter is: 24+18+24+18 = 84 cm
Perimeter = 2 x L + W so L + W = 9, this would be 6 x 3 to give area of 18
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
18cm is the area and perimeter. the width is 3cm.
450 square centimeters
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
Width of rectangle: 144/18 = 8cm Perimeter of rectangle: 2*(18+8) = 52cm
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
If that's its length and width then perimeter is: 24+18+24+18 = 84 cm
Perimeter = 2 x L + W so L + W = 9, this would be 6 x 3 to give area of 18
1:1.23
The dimensions of the rectangle are 5 cm by 4 cm
Area = 6*18 = 108 square cm
It is impossible to say. Let L be ANY number such that 4.5 ≤ L < 9 cm and let B = (9 - L) cm. Then for every one of the infinite number of values of L, there will be a different rectangle whose perimeter will be 18 cm.