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What is the perimeter of a rectangle with a length of 7 and width of 4?
Rectangles Perimeter Is 2L + 2W. 2(7) + 2(4) = Perimeter 14 + 8 = Perimeter Perimeter = 22
What are all the rectangles with a perimeter of 26cm?
To find all the rectangles with a perimeter of 26 cm, we can use the formula for the perimeter of a rectangle: P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Since the perimeter is given as 26 cm, we have 26 = 2(l + w). We can then list all the possible combinations of length and width that satisfy this equation, such as (length 10 cm, width 3 cm), (length 8 cm, width 5 cm), and so on.
How many different rectangles can you draw with an area of 28?
To find the different rectangles with an area of 28, we need to determine the pairs of factors of 28. The factor pairs are (1, 28), (2, 14), (4, 7), and (7, 4), which represent the dimensions of the rectangles. Since the order of length and width doesn't matter, we have four unique rectangles: 1x28, 2x14, 4x7, and 7x4. Therefore, there are three distinct rectangles based on unique dimensions: (1, 28), (2, 14), and (4, 7).
The length of a rectangle is 7 feet more than width if the length were decreased by 3 feet and the width were increased by 2 feet the perimeter would be 32 feet what is the length of the original re?
twelve -------------------- The original rectangle is 12 feet in length and 5 feet in width. The length (12) is 7 feet greater than the width (5 feet). Were the length decreased by 3 (12 - 3 = 9) and the width increased by 2 (5 + 2 = 7), the perimeter would be 32 feet (9 + 7 + 9 + 7 = 32).
If the length of a rectangle is 7 centimeters greater than the width. The perimeter is 54 centimeters. Find the length and the width.?
width:10,length;17 17*2+10*2=54
How many different rectangles can you draw which have a perimeter of 24cm?
To find the number of different rectangles with a perimeter of 24 cm, we first use the formula for the perimeter ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Setting ( 2(l + w) = 24 ) simplifies to ( l + w = 12 ). The pairs of positive integers ( (l, w) ) that satisfy this equation are ( (1, 11), (2, 10), (3, 9), (4, 8), (5, 7), (6, 6) ). This results in 6 unique rectangles, considering length and width can be interchanged.
How do you find the area of a 7 sided shape?
You have to subdivide the shape into squares and rectangles Square & Rectangle= Length X Width Triangle= Base X Height
What is the length of a rectangle if the sides are 3 more than twice its width and the perimeter is forty-eight feet what is the width?
length + width = ½ perimeter ie 24', so length = 24 - width length = 2 x width + 3, so 24 - width = 2 x width + 3 ie 21 = 3 x width so width = 7 and length = 17
The length of a rectangle is 7 meters longer than the width what is the width of this rectangle if its perimeter is equal to 26 meters?
L + W = P/2 = 13. 13 - 7 = 6, 6/2 = 3 which is the width, making the length 10.
What equls 10 length inches 7 width inches 2 height inches?
A solid shape which has a length of 10 inches, a width of 7 width inches and a height of 2 inches. It could be a cuboid or an ellipsoid or some other shape.
The length of a rectangular poster is 7 in greater than the width the perimeter is 114 find the width and length?
Let the width be x and the length be x+7: 2(x+x+7) = 114 4x+14 = 114 4x = 114-14 4x = 100 x = 25 Therefore: width = 25 units and length = 32 units
The length of a rectangle is 2 cm less than 7 times the width the perimeter is 60 cm find the width and length?
60 and 62
