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30 radical 2
if it is a cube each side is 9 inches ( cube root of 729); 9 x 9 x 9 - 729
Each of them is 14.14 inches long. (rounded)
The surface of the cube is 6 times this length squared - 6L2.
20 inches each side.
30 radical 2
if it is a cube each side is 9 inches ( cube root of 729); 9 x 9 x 9 - 729
The volume of a cube is the cube of the length of one edge. (9 inches)3 = 729 cubic inches.
Each of them is 14.14 inches long. (rounded)
The surface of the cube is 6 times this length squared - 6L2.
Each edge measures five inches.
The distance between two tetrahedral voids is 0.866*edge length of the cube.As tetrahedral voids are present at 1/4th of the distance from each corner on a body diagonal of a cube.On each body diagonal there are two tetrahedral voids so making a total of 8 tetrahedral voids in an FCC cube. the distance between two tetrahedral voids is half of the body diagonal of a cube and the body diagonal of a cube is1.732 times of the edge length of the cube
20 inches each side.
To find the length of each diagonal of a square, divide the sum of the diagonal lengths by 2. Since a square has two diagonals of equal length, this division will give you the length of each diagonal.
Each side is sqrt 72 ie 8.49 in
Surface area of a cube A = 6*L^2 where L is the length of each side. L = sqrt(A/6) = 8.
If each cube side is of length s, then the diagonal of the BASE is from Pythagorean theorem sqrt ( s^2 + s^2) = sqrt (2) times s = 1.414s The height of the cube is s, so we use the theorem again using the base diagonal and height to get the cube diagonal: sqrt( (1.414s)^2 + s^2) = sqrt (3s^2) = sqrt(3) times s = 1.732s