If each cube side is of length s, then the diagonal of the BASE is from Pythagorean theorem
sqrt ( s^2 + s^2) = sqrt (2) times s = 1.414s
The height of the cube is s, so we use the theorem again using the base diagonal and height to get the cube diagonal:
sqrt( (1.414s)^2 + s^2) = sqrt (3s^2) = sqrt(3) times s = 1.732s
The principal diagonal.
The edge length of a cube with a diagonal of 9 ft is: 5.196 feet.
Rectangle
You can use pythagorean theorem twice to find the diagonal of a cube
find the cube root of 125(which is 5) is the length of one side do Pythagorean theorem to find the diagonal 5squared plus 5 squared=50 square root of 50=7.07106781 is diagonal
No.
cube
The longest diagonal of a 6 cm cube is: 10.39 cm
The principal diagonal.
Somehow I messed up andused 31 instead of 35 That is why you are receiving an improvement Do a Google search for Diagonal of a cube Find this website. mathcentral.uregina.ca/QQ/database/QQ.09.04/brett1.HTML - Draw a cube You will see how to find the diagonal of a cube. You use Pythagorean Theorem Draw a cube Label each side as s Draw the diagonal of the base of the cube Diagonal of base = (s^2 + s^2 )^0.5 Let the diagonal of the base be the horizontal side of the right triangle whose hypotenuse is the diagonal of the cube. The height of the cube is the vertical side of the right triangle whose hypotenuse is the diagonal of the cube. Now determine the length of the diagonal of the cube. (diagonal of base)^2 + (height of cube)^2 = (diagonal of cube )^2 Diagonal of base = (s^2 + s^2 )^0.5….Height of cube = s Use Pythagorean Theorem (diagonal of cube )^2 = (diagonal of base)^2 + (height of cube)^2 (diagonal of base)^2 = [(s^2 + s^2 )^0.5]^2 = s^2 + s^2 height of cube)^2 = s^2 (diagonal of cube)^2 = (s^2 + s^2 + s^2) (diagonal of cube )^2 = (3 * s^2) diagonal of cube = (3 * s^2)^0.5 = 35 (3 * s^2)^0.5 = 35 Square both sides 3s^2 = 31^2 = 1225 s^2 = 408.33 s = 40833^0.5 s = 20.2 cm
If the diagonal is d thenV = [d/sqrt(3)]^3
The edge length of a cube with a diagonal of 9 ft is: 5.196 feet.
The longest diagonal in a cube is equal to the length of the edge, multiplied by the square root of 3.
The diagonal will be 8.66 cm
Rectangle
weight and cube
6.928 (rounded)