The vertical height.
The area of a triangle cannot be determined by its length and withgt or width, even. You need the length and the perpendicular height.
6.8 units
The length of a line segment that starts at the point and is perpendicular to the original line.
perpendicular
Find the length of the base and the perpendicular height. Multiply together. Divide answer by 2. Area of Triangle = ½(Base x Perpendicular Height) For right angled triangles, take the length of the two shortest sides, multiply them together and divide the answer by two.
So that the arc is mid-way in perpendicular to the line segment
28.611
I get 9
36. If the length of the line segment joining the midpoints of two sides of an equilateral triangle is 6 the perimeter of the triangle is 36.
the length of a perpendicular segment from the point to the line
perpendicular
The only requirement for an isosceles triangle is that two sides be the same length and one be different. It is possible for an isosceles triangle to have two perpendicular legs. It would be right and isosceles.
The area of a triangle cannot be determined by its length and withgt or width, even. You need the length and the perpendicular height.
It's the height.
The base of the triangle equals (2x) the mid-segment, so.... 12/2 = 2x/2 6= x
6.8 units
ABC is an equilateral triangle with side length equal to 50 cm. BH is perpendicular to AC. MN is parallel to AC. Find the area of triangle BMN if the length of MN is equal to 12 cm.