That depends entirely on what the width is. If you call the width (in feet) w, then the length in feet would be 3w+2
With more information either the perimeter or the area of the rectangle you could solve the problem
A = lw
A = (3w+2)w replace A with area and solve or
P = 2(l+w)
P = 2((3w+2)+w) replace P with the perimeter and solve
The length of the length will be 5 and the width will be 25.
length times width equals the area of a rectangle. length times width equals the area of a rectangle. area
The area of a rectangle is found by multiplying the length times the width.
It is the square area of the rectangle
That would depend on the length of the rectangle which has not been given but the area of a rectangle is length times width
The length of the length will be 5 and the width will be 25.
It is the area of the rectangle which is length times width
length times width equals the area of a rectangle. length times width equals the area of a rectangle. area
Area of the rectangle = 36 =Length * Width Assume Width= a Hence Length = 4*a =4a Area = a*4a =36 Therefore, a*a =9 Hence a =3 =Width
yes
A = lw Area of a rectangle = length times width
Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet
length times width
The area of a rectangle is found by multiplying the length times the width.
multiply length times height times width
It is the square area of the rectangle
Length times width gives the area of a rectangle. The rectangle with a length of 38 and a width of 28 has an area of 1064 square units.