10 in. A+LS
Area of the rectangle = 36 =Length * Width Assume Width= a Hence Length = 4*a =4a Area = a*4a =36 Therefore, a*a =9 Hence a =3 =Width
Length of rectangle garden is 5 m greater than the width. the area is 84 m2. find the dimensions of the garden.
15 x 7 = 105...
Since the length is greater than the width, any value greater than sqrt(43.7) which is approx 6.61 metres. For example, length = 40m, width = 43.7/40 m or length = 100m, width = 43.7/100 m or length = 1000000m, width = 43.7/1000000 m
Any length greater than six.
The length of the length will be 5 and the width will be 25.
7
Length 17 cm. Width 10 cm.
10 in. A+LS
Area of the rectangle = 36 =Length * Width Assume Width= a Hence Length = 4*a =4a Area = a*4a =36 Therefore, a*a =9 Hence a =3 =Width
Your answer is any length greater than 16Equation:Area = L * WCalculations400 < L * 25400 / 25 = 16
Length of rectangle garden is 5 m greater than the width. the area is 84 m2. find the dimensions of the garden.
Yes, Oblong is the name of a rectangle who's length is greater than it's width.
105 = 7 x 15.
15 x 7 = 105...
10x2