Given an altitude of 12 units, an equilateral triangle has side lengths of 13.9 (13.85641) units.
Each side of the triangle is 16.16581 units in length.
The length of each side is 9.2376 cm. (rounded)
Height = sqrt(3)/2 * length of side So here, approx 4.3301 cm
An equilateral triangle has 3 equal interior angles each of 60 degrees. There are two right angled triangles in an equilateral triangle. So we can use trigonometry to find the length of one side of the equilateral triangle then multiply this by 3 to find its perimeter. Hypotenuse (which is one side of the equilateral) = 15/sin 60 degrees = 17.32050808 17.32050808 x 3 = 51.96152423 Perimeter = 51.96152423 units.
15.2 inches.
No. The altitude is smaller.
Each side of the triangle is 16.16581 units in length.
The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
The length of each side is 9.2376 cm. (rounded)
Given side lengths of 8 units, an equilateral triangle will have an altitude of 7 (6.9282) units.
Multiply the altitude by [ 2 / sqrt(3) ] to get the length of the side.[ 2 / sqrt(3) ] is about 1.1547 (rounded)
The sides are 2*sqrt(3) units in length.
With an altitude of 10 units, this triangle's sides each measure 11.55 (11.54701) units.
Height = sqrt(3)/2 * length of side So here, approx 4.3301 cm
The altitude/height of an equilateral triangle can be calculated by taking the perpendicular bisector of any side. This line will bisect its opposite angle forming two congruent right angled triangles. The side length of the original equilateral triangle is the hypotenuse and the short leg of right angled triangle is half the hypotenuse. By Pythagoras' Theorem : 42 = 22 + L2.........where L is the length of the altitude. L2 = 42 - 22 = 16 - 4 = 12 L = √12 = 2√3 = 3.464 (3dp)
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.