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The equation x^2 + y^2 = 169 represents a circle centered at the origin with a radius of 13 units.

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If x^2 plus y^2 = 169 then the center of the circle is at (0, 0) and its radius is the square root of 169 which is 13

Q: What is the length of the circles radius for the circle x2 plus y2 169.?

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Radius = 1111

8

The ' 1 ' in that equation is the radius.

The circles are concentric with centre (0,0). The radius of the outer circle is sqrt(72), that of the inner circle is sqrt(18). By Pythagoras, the length of the semichord is sqrt(72 - 18) = sqrt(54) units. Therefore the chord is 2*sqrt(54) = 6*sqrt(6) = 14.679 units (approx).

10 Both the x-intercept (y=0) and the y-intercept (x=0) have a length of 10 units.

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Radius = 1111

8

4

The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1

9 (APEX)

The ' 1 ' in that equation is the radius.

If you mean: x^2 + y^2 = 121 then the radius is the square root of 121 which is 11

sqrt 36 ie 6

The circles are concentric with centre (0,0). The radius of the outer circle is sqrt(72), that of the inner circle is sqrt(18). By Pythagoras, the length of the semichord is sqrt(72 - 18) = sqrt(54) units. Therefore the chord is 2*sqrt(54) = 6*sqrt(6) = 14.679 units (approx).

10 Both the x-intercept (y=0) and the y-intercept (x=0) have a length of 10 units.

11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2

The Area of a rectangle is LxW . The area of a circle is PI x RxR where R is the radius of the circle. The Circumference or distance around a circle is 2xPIxR. To find the surface area of a cylinder with radius R (the radius of the circles at the top and bottom) and Length L(how tall the cylinder is) you first find the area of the circles on the bottom and top - then add it to the area of the tube part. If you unwrap the tube, it becomes a rectangle with the width 2xPIxR (since it was wrapped around the circles on top and bottom), and the Length L( how tall it is) . So it will be 2 circles plus the rectangle. 2 (PIxRxR) + 2xPIxRxL. Then round it to the nearest whole number. If the number on the right side of the decimal point is 5 or more, round up to the next whole number otherwise leave it the same. Then drop the numbers on the right side of the decimal point.